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sree
post Sep 18 2006, 12:49 PM
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A creeper plant is climbing up and around a cylindrical tree trunk in a helical manner. The tree trunk has a height of 240 inches and a circumference of 32 inches. If the creeper covers a vertical distance of 60 inches in one complete twist around the tree trunk, what is the total length of the creeper?
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Rocky
post Sep 18 2006, 07:18 PM
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I sure i will answer this question...
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Rocky
post Sep 18 2006, 07:32 PM
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IIIIIII haaaaaaaa,
Finally i found the Answer...

Is this right?

Detailed below....

QUOTE
Circumference of tree = 32
Virticle distance of Tree = 60 inch

If we remove tree Circle Folding...
It will be rectangular..

and by pythagora's Therom,


Hypotenuse = Root of (square of 32 + square of 60)
    = 68


Now, the number of twists the creeper makes around the tree trunk is 7.5 (240/32)

If the length of the creeper is 68 inches in one twist,

The total lengh of Creeper in 7.5 is 510
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bakuryu
post Sep 18 2006, 11:37 PM
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QUOTE
Now, the number of twists the creeper makes around the tree trunk is 7.5 (240/32)


Why 7.5 twists ??

If the creeper covers 60inches (vertical) in 1 twist and the total height is 240inches (vertical), then the no. of twists should be : 240/60 = 4

so the height should be 4 * 68 = 272inches.
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Rocky
post Sep 19 2006, 06:17 AM
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I think Both are Correct....
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